Statistics problems and solutions

[Name of the Author]

Statistics problems and solutions

QUESTION NO. 1

Years of Service

No. of employees

Lower Class limits

Upper Class limit

1

5

5

6

10

20

11

15

25

16

20

10

21

25

5

Part A.

The class width is the difference between the upper class boundaries and the lower class boundaries

In this table the class width is calculated by calculating the difference between the class boundaries of any class.

Class boundary is the midpoint between the upper class limit of a class and the lower class limit of the next class

Here in class three the class boundary is

The lower class boundary is the midpoint between 11 and 10 = 10.5

The upper class boundary is the midpoint between 15 and 16 = 15.5

So the class width of the distribution is 15.5 - 10.5 = 5

Part B.

Class boundary is the midpoint between the upper class limit of a class and the lower class limit of the next class

Here in class three the class boundary is

The lower class boundary is the midpoint between 11 and 10 = 10.5

The upper class boundary is the midpoint between 15 and 16 = 15.5

Part C.

The lower class limit of c lass 2 is 6

Part D.

The upper class limit of class 5 is 20

Part E.

The relative frequency is calculated by



Where,

ni ,is the relative frequency

fi, is the frequency of the particular class

N, is the total no. of data points

i, is the no. of class

So, for class 4

= 0.15

0.015 is the relative frequency of class 4.

Part F.

QUESTION NO 2

The stem and leaf table for the data is below

Scores of students

stem

leaf

6

6 6 6 8

7

3 3 3 3 3 3 9 9 9 9 9

8

3 3 3 4 4 4 4

9

1 1

QUESTINO NO 3

Part A.

Mode is the most repetitive value is the data set and as no value repeats in this data set there is no mode.

Part ...