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Equations in Real Would Situations

Equations in Real Would Situations

Introduction

A quadratic equation has the general form ax ² + bx + c = 0. To solve such equations, there are several methods, but we are using the method that came from India. The quadratic equations below are solved by the method came from India. The method consists of six simple steps that have been described in detail in solution to these questions.

Body

PROJECT #1

Equations to solve

x^2 - 2x - 13 = 0

c) x^2 + 12x - 64 = 0

Solution (a)

X^2 - 2x - 13 = 0

(a) Move the constant term to the right side of the equation.

X2 - 2x = 13[-13 + 13 on the left hand side of equation, and 0 + 13 on the right side of the equation ]

(b) Multiply each term in the equation by four times the coefficient of the x2 term.

4x2 - 8x = 52[Since the coefficient of the x2 term is 1, I multiply by 1 * 4 = 4].

(c) Square the coefficient of the original x term and add it to both sides of the equation.

4x2 - 8x + 4 = 52 + 4[Since 2 is the coefficient of the original x term, as in - 2x, the square of 2(or the square of - 2) is 4.]

4x2 - 8x + 4 = 56[I did the arithmetic. 52 + 4 = 56]

(d) Take the square root of both sides.

2x -2 = ± 2 v14[Note: you get two "solutions," a positive one and a negative one]

(e) Set the left side of the equation equal to the positive square root of the number on the right side and solve for x.

(f) Set the left side of the equation equal to the negative square root of the ...

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