PHYSICS

Physics

Physics

Task 1

Q1: Determine distribution of shear force, bending moment and stress due to bending in simply supported beam shown in the figure below, the beam has a self weight of 90kN distributed along its length.

Answer

The formula to calculate average shear stress is:

Where

t = the shear stress

F = the force applied

A = the cross sectional area

150mm

460 kN 180 kN

400mm 25mm

4m 6m 2m

30mm

F = 460000 N

A = l x b = 8 x 4 = 32 m2

t = 460000/32 = 14375 pascal

Q2: Determine distribution of shear force, bending moment and stress due to bending in the simply supported beam shown below. The self-weight of the beam can be ignored.

42kN 24kN

100mm

12kN/m 20

200mm 15

3m 2m 2m

20

Answer

F = 42000 N

A = l x b = 5 x 2 = 10 m2

t = 42000/10 = 4200 pascal

Task 2

Q1: Select a standard rolled steel I-section for the simply supported beam shown in figure below. A factor of safety of 5 applies and the ultimate tensile strength of the material is 540 MPa. The weight of the beam itself may be neglected when calculating the maximum moment

65 kN

3 m 3 m

Answer

F = 65 N

A = l x b = 3 x 3 = 9 m2

t = 65/9 = 7.22 pascal

Q2: A column is made from a universal I-section 203 x 203 x 46. A load of 110 kN is applied on the x-axis 110mm from the centroid. Calculate the stress at the outer edges of the x-axis.

Area = 203 x 46 = 9338 m2

Load = 110000 N

Stress = Load/Area

Stress = 110000/9338

Stress = 11.78 Pascals

Task 3

Q1: A hollow circular shaft has an internal diameter of 80 mm and an external diameter of 120 mm. Calculate the shear stress produced at the outer and inner of the shaft when the applied ...