STATS 200

Stats 200



Stats 200

Answer # 1:

= 11/ 50 = 22%

Answer # 2:

= 50/ 8 = 6.25

Answer # 3:

The median lies in 80 - 89 and 90 - 99 class intervals.

Answer # 4:

The mean value will increase to;

= 86/ 8 = 10.75

However, the median will remain same that is it will lie under 80 - 89 and 90 - 99 class intervals.

Answer # 5:

= 3/ 4 = 0.75

Answer # 6:

Events A & B are dependent on each other, because the probability of occurring event A is dependent on event B as if A occurs than event B will not occur.

Answer # 7:

= 28.65

Answer # 8:

The given playing times are unusual as they are mentioned in seconds; however, it is observed that the time is usually given in minutes or hours.

Answer # 9:

(b) BigBurg

Answer # 10:

(d) It is impossible to tell using only the given information

Answer # 11:

(c) Both cities have the same value requested

Answer # 12:

Mean

3960

Standard deviation:

200

Sample size

49

Confidence interval of

95 %

Result

Estimated population mean is

3960

Estimated CI is

3902.553

to

4017.447

Answer # 13:

1 - [(1-0.5) * (1-0.5)]

= 1 - [0.5 * 0.5]

= 1 - 0.25

= 0.75

Answer # 14:

There is 0.5 percent of probability that that if the student is in the statistics class, is also in the calculus class.

Answer # 15:

There are 100 elements in the sample space for the experiment.

Answer # 16:

= 3/ 10 = 0.3

Answer # 17:

= 3/ 5 = 0.6

Answer # 18:

x

P (x)

E (X)

2

0.1

0.2

3

0.3

0.9

5

0.4

2

8

0.1

0.8

10

0.1

1

4.9

Answer # 19:

= 3.361

Answer # 20:

If the 80% of people will show up for the flight then:

12 * 0.8 = 10, this is equivalent to 10 seats that are available for the flight.

Answer # 21:

= 10* 0.80 = 8;

Thus, it can be said that 8 passengers are expected to show up.

Answer # 22:

From the hypothesis test, it can be concluded that the alternate hypothesis is accepted that ...