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Module 3 - Case
Module 3 - Case
1. Determining whether or not the lines be perpendicular if they are graphed.
3x - 2y = 6
2x + 3y = 6
3x - 2y = 6
3x - 6 = 2y
y = (3x - 6)/2
2x + 3((3x - 6)/2) = 6
2x + 3(1.5x - 3) = 6
2x + 4.5x - 9 = 6
6.5x = 6 + 9
6.5x = 15
x = 2.30
Substituting x into other equation:
3(2.30) - 2y = 6
6.90 - 2y = 6
6.90 - 6 = 2y
2y = 0.90
y = 0.45
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